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-.8x+9x-10x^2=0
We add all the numbers together, and all the variables
-10x^2+8.2x=0
a = -10; b = 8.2; c = 0;
Δ = b2-4ac
Δ = 8.22-4·(-10)·0
Δ = 67.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.2)-\sqrt{67.24}}{2*-10}=\frac{-8.2-\sqrt{67.24}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.2)+\sqrt{67.24}}{2*-10}=\frac{-8.2+\sqrt{67.24}}{-20} $
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